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(D) The angular width of the central diffraction maximum for a circular aperture is given by $	heta \approx \frac{1.22 \lambda}{D}$,where $D$ is the

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its size decreases,but intensity increases

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(D) The angular width of the central diffraction maximum for a circular aperture is given by $	heta \approx \frac{1.22 \lambda}{D}$,where $D$ is the diameter of the pinhole and $\lambda$ is the wavelength of light.As the diameter $D$ of the pinhole increases,the angular width $	heta$ decreases,which means the size of the diffraction pattern decreases.Since the total amount of light passing through the pinhole increases as the area of the pinhole increases (area $\propto D^2$),and this light is now concentrated into a smaller area,the intensity of the diffraction pattern increases.Therefore,the size decreases and the intensity increases.

Consider the diffraction pattern obtained from the sunlight incident on a pinhole of diameter $0.1 \, \mu m$. If the diameter of the pinhole is slightly increased,it will affect the diffraction pattern such that :

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$A$ microwave of wavelength $2.0 \ cm$ falls normally on a slit of width $4.0 \ cm$. The angular spread of the central maxima of the diffraction pattern obtained on a screen $1.5 \ m$ away from the slit,will be: (in $^{\circ}$)

The condition for obtaining secondary maxima in the diffraction pattern due to a single slit is:

If $\lambda = 6000 \, \mathring{A}$ and $a = 18 \times 10^{-5} \, \text{cm}$,find the angular width of the central maximum in degrees $(^\circ)$.

For a light of wavelength $5000 \, \mathring{A}$ incident normally on a slit,the first diffraction minimum is formed at an angle of $\theta = 30^\circ$. The width of the slit is:

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